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August 29, 2014

August 29, 2014

Posted by **mace** on Thursday, February 21, 2013 at 7:58pm.

- MATH -
**JJ**, Thursday, February 21, 2013 at 8:18pmy^3 + y^2 - 4y - 4

factor by grouping the first two and the last two. Be careful with the second grouping because of the _(-) in front of the 4y.

(y^3 +y^2) + (-4y -4)

Take out the common factors:

y^2(y+1) + -4(y+1)

See the y+1?

Write that down once and your other factor is what is left over.

(y+1)(y^2-4)

You can multiply these factors to check that you did it correctly.

t^2 + 4z^2

This is a sum of two squares and it cannot be factored.

You can factor a difference of two squares. If this was t^2 -4z^2

it would factor to (t-2z)(t+2z)

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