Posted by **Cristina** on Thursday, February 21, 2013 at 7:26pm.

Find the magnitude of the magnetic flux through the floor of a house that measures 21m by 13m . Assume that the Earth's magnetic field at the location of the house has a horizontal component of 2.4×10−5 T pointing north, and a downward vertical component of 4.3×10−5 T .

I can't seem to get the correct answer so i think I might be going about the problem the wrong way.

This is what I did.

Bx= 2.4x10-5 T

By= 4.3x10-5 T

Bnet= (Bx^2 + By^2)^.5 = 4.9x10-5 T

angle= tan^-1(By/Bx)= 60.83

A= 21m x 13m= 273m^2

Magnetic flux= Bcos angle A

magnetic flux= .00651 Wb

My answer was incorrect, any ideas what the right way to approach this problem is??

## Answer this Question

## Related Questions

- Physics - At a certain location, the Earth's magnetic field has a magnitude of 5...
- Physic please check - A house has a floor area of 119 m2 and an outside wall ...
- physics please help - In a physics laboratory experiment, a coil with 170 turns ...
- College physIcs - An electron travels at a speed of 4.0×104 m/s through a ...
- physics - A magnetic field is oriented at an angle of 42 degrees to the normal ...
- Physics - Help please A wire carries a current of 5.2 A from east to west ...
- Physics - The Earth has an electric field with magnitude roughly 100 N/C at its ...
- Physics - If a magnetic flux passes through a circular coil when its diameter D...
- Physics - Two flat surfaces are exposed to a uniform, horizontal magnetic field...
- Physics-Please check - Electricity may be generated by rotating a loop of wire ...

More Related Questions