Posted by Angel on Thursday, February 21, 2013 at 5:20pm.
to get a 3, you need 2,1 or a 1,2
to get 4, you need 1,3, 3,1;2,2
b. to get 5, 4,1;1,4;2,3;3,2
to get a 9, 5,4;4,5;6,3,3,6 equal probablility for 5 and 9
c. 5 you need 4,1;1,4; 2,3;3,2
8 tyou need 6,2;2,6, 5,3,3,5, 4,4
d. and so one.
okay but can you explain it better plz
neither mind but can u help with the second
For the first part, you really need to make a table to show all of the possible sums
I suggest making a table with 1 -6 across the top and 1-6 down the side..
Then fill in the table by adding the die.
1,1 = 2
1, 2 = 3
You may be able to find a table like this in your book or by searching google. This takes a lot of time to do by yourself.
There are 36 outcomes. You will have to see how many times each sum comes up to answer the question.
For part 2 To find the x or y - intercepts
First you let x = 0 and find y
then you let y = 0 and find x.
Remember (x,y) is the ordered pair.
(x, 0) and (o, y)
replace x and y with the values you found.
i don't get it
can you explain it better plz
to get sum of 1 = 0.
to get sum of 2 = 1/36 since there are 6 options on each die and two die so 6*6 = 36. And the only way to get two is 1+1
to get sum of 3 = 1+2, 2+1, so 1/18
to get 4 = 1,3 2,2 3,1 so 1/12
to get 5 = 2,3 3,2 1,4 4,1 so 1/9
etc etc etc
so after writing them all down, we find that 5 and 9 are equal:
to get 5 = 2,3 3,2 1,4 4,1 so 1/9
to get 9 = 3,6 6,3 4,5 5,4 so 1/9
no other ones because the die only has 6 numbers.
so the answer is B