Posted by **T-perry** on Thursday, February 21, 2013 at 3:55pm.

A college student decides that school work limits him to a total of no more than 36

hours per week at his two parttime jobs. He earns $6 per hour hanging wall paper and

he has a sales job that pays $8 per hour. He needs to earn at least $245 per week to

cover his expenses. Write a system of inequalities that shows the various numbers of

hours he can work at each job. Let h represent the number of hours spent hanging wall

paper and let s represent the number of hours spent working at the sales job.

- Math -
**JJ**, Thursday, February 21, 2013 at 3:58pm
hours: h + s < or equal to 36

6h + 8s > or equal to 245

You can solve these just like you would equations.

How would you solve h + s = 36

6h + 8s = 245

Multiply the first equation by -6 and then combine the equations to eliminate the x and solve for y. Substitute back in to solve for x.

then go back to the original inequalities to find the various numbers houwer worked

- Math -
**T-perry**, Thursday, February 21, 2013 at 4:00pm
well you would isolate y and i got s< or equal to -h+36

- Math -
**JJ**, Thursday, February 21, 2013 at 4:04pm
I meant to say s and h.

You could do that which issubstitution or you could use the addition/elimination method

-6h -6s <= 216

6h +8s >= 245

2s =461

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