Will someone please help me slove this problem?

Use the elimination method to solve the system of equations.

5u+2v=-18
3u+v=-5

I have tried to solve this problem several times and have not gotten the correct answer please help. Thank you.

Of course, I'd be happy to help you with this problem!

To solve the system of equations using the elimination method, we'll begin by eliminating one of the variables. Let's eliminate the "v" variable by multiplying the second equation by 2, so that the coefficients of "v" are the same in both equations.

So, we have the revised equations:
5u + 2v = -18 (Equation 1)
6u + 2v = -10 (Equation 2)

Now, we can subtract Equation 1 from Equation 2 to eliminate the "v" variable:
(6u + 2v) - (5u + 2v) = -10 - (-18)
Simplifying, we get:
u = 8

Now that we have found the value of "u", we can substitute it back into one of the original equations to solve for the "v" variable. Let's use Equation 2:
3u + v = -5
Substituting u = 8, we have:
3(8) + v = -5
24 + v = -5
Now, we can solve for "v":
v = -5 - 24
v = -29

Therefore, the solution to the system of equations is u = 8 and v = -29.

If you have not obtained the correct answer, please double-check your calculations and ensure that you accurately performed the operations at each step.

5u+2v=-18

3u+v=-5

Multiply second equation by two and subtract from the first equation.

6u+2v = -10

-u = -8

Multi[ply by -1.

Insert u value into the first equation to find v, then check by putting both values into the second equation.