Posted by Penelope on Thursday, February 21, 2013 at 4:15am.
a) number of (2math, 3 science() = C(4,2) x C(6,3) =120
b) one specific scientist must be in, so need 2 other scientist
= C(4,2) x C(6,2) = 90
c) 2 specific math guys must be in, but we need only 2 maths, so only need the 3 science
= C(6,3) = 20
d) 2 specific science guys are out, so need 3 from remaining 4 science guys
= C(4,2) x C(4,3) = 24
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