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March 29, 2015

March 29, 2015

Posted by **Anonymous** on Thursday, February 21, 2013 at 1:07am.

- physics -
**Henry**, Friday, February 22, 2013 at 12:50pmYo = 26 m/s.=Ver. component of initial velocity.

Y = Yo + gt.

Tr = (Y-Yo)/g = (0-26/-9.8 = 2.65 s. =

Rise time.

Tf1 = Tr = 2.65 s. = Fall time to launching point.

h = Yo*t + 0.5g*t^2 = 20 m.

26t + 4.9t^2 = 20

4.9t^2 + 26t - 20 = 0

Use Quad. Formula:

Tf2 = 0.68 s. To fall 20 m.

T = Tr + Tf1 + Tf2=2.65 + 2.65 + 0.68 =

5.98 s. = Time in air.

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