You want to create a subnetwork of at least 100 computers. Currently your network is 172.21.0.0/16. Describe the subnetwork with the least amount of hosts that can accommodate 100 computers and calculate the subnet mask. What is the broadcast address for this network?

Ip config 192.456.0

The question is to describe the subnetwork with the least amount of hosts to accommodate 100 computers, calculate the subnet mask and what is the broadcast address for this network.

Note the broadcast and host by plus value 1. Ip config zip zo.

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Subnet Mask-
Broadcast Address-

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To create a subnetwork that can accommodate at least 100 computers within the existing network 172.21.0.0/16, you need to determine the minimum number of host addresses required and then calculate the appropriate subnet mask.

First, let's determine the number of host addresses required. Since you need to accommodate at least 100 computers, you will need a minimum of 100 + 2 (network and broadcast addresses) = 102 host addresses.

Next, we need to find a subnet mask that can provide at least 102 available host addresses. To determine the subnet mask, you can use the formula:

2^(32 - subnet mask) >= required host addresses

Substituting the required host addresses into the formula:

2^(32 - subnet mask) >= 102

Now, find the subnet mask that satisfies the inequality. By testing different subnet mask values, we can determine that a /25 subnet mask will accommodate at least 102 host addresses.

Therefore, the subnet mask for this subnetwork is 255.255.255.128 or /25.

To calculate the broadcast address for the subnetwork, you'll need to apply the subnet mask to the network address.
For this, you'll use the bitwise OR operation between the inverted subnet mask and the network address. The formula is as follows:

Broadcast address = Network address OR (inverse of subnet mask)

In this case, the network address is 172.21.0.0 and the subnet mask is 255.255.255.128 (or /25 in CIDR notation).

Converting the subnet mask into its binary representation: 11111111.11111111.11111111.10000000.

Inverting the binary subnet mask: 00000000.00000000.00000000.01111111.

Performing the bitwise OR operation:

172.21.0.0 OR 0.0.0.127 = 172.21.0.127

Therefore, the broadcast address for this subnetwork is 172.21.0.127.