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November 29, 2014

November 29, 2014

Posted by **Anonymous** on Wednesday, February 20, 2013 at 9:58pm.

3(x+y+5)

(x+y)(x+y+z)

x(y+1)-x

- Math -
**victoria**, Wednesday, February 20, 2013 at 10:16pm3(x+y+5)= 3x+3Y+15

(x+y)(x+y+z)= x2+y +x+y2 + xz+yz (x2 means x squared, y2 means y2)

x(y+1)-x = xy+x-x

im pretty sure these are correct but you might want to double check

all you do is take the number thats out of the ()from the left and distribute/multiply it to the numbers or variables inside the () .. like this : 3(x+4) would be 3x+12 ..

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