Posted by andrew on Wednesday, February 20, 2013 at 7:29pm.
49, 58, 67, 76, 85, or 94
Let t = ten's digit
Let x = one's digit
t + x = 13
2t= x-1 or 2t+1 = x
You can substitue for "x"
t + 2t + 1 = 13
3t = 12
t = 4 find x = 9
so we have 49
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