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November 1, 2014

November 1, 2014

Posted by **andrew** on Wednesday, February 20, 2013 at 7:29pm.

- math -
**Ms. Sue**, Wednesday, February 20, 2013 at 7:31pm49, 58, 67, 76, 85, or 94

- math -
**JJ**, Wednesday, February 20, 2013 at 8:12pmLet t = ten's digit

Let x = one's digit

t + x = 13

2t= x-1 or 2t+1 = x

You can substitue for "x"

t + 2t + 1 = 13

3t = 12

t = 4 find x = 9

so we have 49

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