an unknown solid substance weighs 121g. calculate the specific heat if 425.2 cal raise the temperature of the solid from 24.0 degrees C to 55.7 degrees C.
q=mC∆T
∆T=55.7ºC-24.0ºC
m=121g
q=425.2
C=specific heat=?
Plug in the values and solve.
C=q/m∆T