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How many moles of gas must be forced into a 4.8L tire to give it a gauge pressure of 30.8psi at 30 degrees celsius? The gauge pressure is relative to atmospheric pressure. Assume that atmospheric pressure is 14.5L so that the total pressure in the tire is 45.3psi.

What formula do I use?

  • Chemistry -

    n=PV/RT where p=guage+atmospheric pressure

  • Chemistry -

    Ok thank you so much!

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