Sunday

February 1, 2015

February 1, 2015

Posted by **Shane** on Wednesday, February 20, 2013 at 2:25am.

- Maths -
**hannah**, Wednesday, February 20, 2013 at 8:05amUse a2 + b2 = c2 of the right triangle to find the length of the missing side. c=hypotenuse which in this case is 5. 3^2 + b^2 = 5^2

9 + b^2=25

b^2=16

b=4

sin=opposite over hypotenuse which is 4/5

tan=opposite over adjacent which is 4/3

sec=the reciprocal of cosine which is 5/3 (just change the top and bottom numbers of cosine to get secant)

**Answer this Question**

**Related Questions**

Integration - Intergrate ¡ì sec^3(x) dx could anybody please check this answer. ...

Trigonometry desperate help, clueless girl here - 2. solve cos 2x-3sin x cos 2x...

Trigonometry - 1.Solve tan^2x + tan x – 1 = 0 for the principal value(s) to two ...

precalculus - For each of the following determine whether or not it is an ...

Maths Calculus Derivatives - Find the first derivative for the following ...

trigonometry hlp me - 6.Prove that tan y cos^2 y + sin^2y/sin y = cos y + sin y...

Trig - Given: cos u = 3/5; 0 < u < pi/2 cos v = 5/13; 3pi/2 < v < ...

trig 26 - simplify to a constant or trig func. 1. sec ²u-tan ²u/cos ²v+sin ²v ...

trig help much appreciated! :)) - 1. Find the complete exact solution of sin x...

trignonmetry - 6. Prove that tan λ cos^2 λ + sin^2λ/sin λ = ...