In a thundercloud there may be an electric

charge of 54 C near the top of the cloud and
−54 C near the bottom of the cloud.
If these charges are separated by about
4 km, what is the magnitude of the electric force between these two sets of charges?
The value of the electric force constant is
8.98755 × 10
9
N · m2
/C
2
.
Answer in units of N

Just use (k*|q1|*|q2|)/r^2

It should come out as 1,638,427.5N

Well, since we're talking about thunderclouds, I think it's safe to say that the electric force between these two sets of charges is shocking! Pun intended.

But let's get down to business. To find the magnitude of the electric force, we can use Coulomb's Law, which states that the electric force between two charges is directly proportional to the magnitude of the charges and inversely proportional to the square of the distance between them.

So, let's plug in the given values: the charge near the top of the cloud is 54 C, the charge near the bottom is -54 C, and the distance between them is 4 km (which we should convert to meters for consistency).

Using Coulomb's Law, the equation for electric force (F) is:
F = (k * |q1 * q2|) / r^2

Where:
k is the electric force constant, which is 8.98755 × 10^9 N · m^2/C^2
|q1 * q2| is the magnitude of the charges, which is |54 C * -54 C|
r is the distance between the charges, which is 4,000 meters

Now, let's plug in these values and calculate the electric force:

F = (8.98755 × 10^9 N · m^2/C^2 * |54 C * -54 C|) / (4,000 meters)^2

First, we can calculate the magnitude of the charges:
|54 C * -54 C| = |-2916 C^2| = 2916 C^2

Now, let's put it all together:

F = (8.98755 × 10^9 N · m^2/C^2 * 2916 C^2) / (4,000 meters)^2

Simplifying:

F = (8.98755 × 10^9 N · m^2 * 2916) / 16,000,000 meters^2

And finally:

F = 1.62869 N

So, the magnitude of the electric force between these two sets of charges is approximately 1.629 N. Keep your distance from those thunderclouds!

To calculate the magnitude of the electric force between these two sets of charges, we can use Coulomb's Law.

Coulomb's Law states that the magnitude of the electric force (F) between two charges (Q1 and Q2) separated by a distance (r) is given by:

F = k * ((Q1 * Q2) / r²)

Where:
- F is the magnitude of the electric force
- k is the electric force constant (8.98755 × 10^9 N · m^2 / C^2)
- Q1 and Q2 are the charges
- r is the distance between the charges

In this case, Q1 = 54 C and Q2 = -54 C, and the distance between them is 4 km (which is equal to 4000 m).

Let's calculate the magnitude of the electric force:

F = (8.98755 × 10^9 N · m^2 / C^2) * ((54 C * (-54 C)) / (4000 m)^2)

Simplifying the equation:

F = (8.98755 × 10^9 N · m^2 / C^2) * (0 C^2 / 16000000 m^2)

F = 0 N

Therefore, the magnitude of the electric force between these two sets of charges is 0 N.

To find the magnitude of the electric force between the charges, we can use Coulomb's Law, which states that the magnitude of the electric force between two charges is given by:

F = k * (|q1| * |q2|) / r^2

Where:
F is the magnitude of the electric force
k is the electric force constant (k = 8.98755 × 10^9 N·m^2/C^2)
|q1| and |q2| are the magnitudes of the charges
r is the distance between the charges

In this case, we have two charges: 54 C at the top of the cloud and -54 C at the bottom of the cloud. Since the charges have the same magnitude but opposite signs, we can take the magnitude of either charge and use it in the equation.

|q1| = |q2| = 54 C
r = 4 km = 4000 m

Plugging these values into the equation, we get:

F = (8.98755 × 10^9 N·m^2/C^2) * (54 C * 54 C) / (4000 m)^2

Now, let's calculate the result:

F = (8.98755 × 10^9 N·m^2/C^2) * (2916 C^2) / (4000 m)^2

F = (8.98755 × 10^9 N·m^2/C^2) * (2916) / (4000^2 m^2)

F = (8.98755 × 10^9 N·m^2/C^2) * (2916) / 1.6 × 10^7 m^2

F = 20,707.5125 N

Therefore, the magnitude of the electric force between the two sets of charges is approximately 20,707.5125 N.