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July 31, 2014

July 31, 2014

Posted by **James** on Tuesday, February 19, 2013 at 9:38pm.

- physics 12 -
**bobpursley**, Tuesday, February 19, 2013 at 9:51pmIn principle, it is easy.

calculate the distance each star is from the center of mass, that is the radius of rotation for each star.

Hint: the mass m is 3 parts of separation distance, whilst the 3m star is one part away. So divide the distance by 4, and you know the two radius of roataions. You need this in the centripetal force calculation.

Forcegravity=centripetal force

for the small star...

G3m^2/distance^2=m w^2 (3/4 distance)

solve for w

but shouldn't the w for the large star be the same? Lets check..

G3m^2/distance^2=3m w^2 (1/4 distance)

hmmm. it is the same angular velocity.

Oh, period. Convert w (knowing w=2PI/period) to period.

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