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January 31, 2015

January 31, 2015

Posted by **Anonymous** on Tuesday, February 19, 2013 at 6:04am.

- maths -
**Reiny**, Tuesday, February 19, 2013 at 10:53amprob(white) = 4/10 = 2/5, prob(red) = 6/10 = 3/5

no white balls --- (3/5)^4 = 81/625

one white ball -- C(4,1) (2/5) (3/5)^3 = 216/625

two white balls -- C(4,2) (2/5)^2 (3/5)^2 = 216/625

three white balls -- C(4,3) (2/5)^3 (3/5) = 96/625

four white balls -- (2/5)^4 = 16/625

notice that the sum of these is 1 , as it should be

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