Posted by **Anonymous** on Tuesday, February 19, 2013 at 6:04am.

urn contains 4 white and 6 red rolls. Four balls are drawn at random (without replacement) from the urn. Find the probability distribution of number of white balls?

- maths -
**Reiny**, Tuesday, February 19, 2013 at 10:53am
prob(white) = 4/10 = 2/5, prob(red) = 6/10 = 3/5

no white balls --- (3/5)^4 = 81/625

one white ball -- C(4,1) (2/5) (3/5)^3 = 216/625

two white balls -- C(4,2) (2/5)^2 (3/5)^2 = 216/625

three white balls -- C(4,3) (2/5)^3 (3/5) = 96/625

four white balls -- (2/5)^4 = 16/625

notice that the sum of these is 1 , as it should be

## Answer This Question

## Related Questions

- statistics - An urn contains white and red balls. Four balls are randomly drawn ...
- statistics - An urn contains white and red balls. Four balls are randomly drawn ...
- statistics - An urn contains 10 balls of which 6 are white, 3 are red and 1 is ...
- statistics - An urn contains 10 balls of which 6 are white, 3 are red and 1 is ...
- MATH(STATISTICS) - Urn A contains R red balls and W white balls, urn B contains ...
- MATH - An urn contains 5 white and 6 black balls. Four balls are randomly drawn ...
- statistic - An urn contains white and green balls. Four balls are randomly drawn...
- Strayer University - An urn contains white balls and red balls. If Juan chooses ...
- Math-Probability - An urn contains four red balls and three white balls. A ...
- MATH - Urn A contains six white balls and three black balls. Urn B contains ...

More Related Questions