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December 20, 2014

December 20, 2014

Posted by **Jeconiah** on Tuesday, February 19, 2013 at 5:56am.

- Algebra -
**Steve**, Tuesday, February 19, 2013 at 11:57amHere's (a):

{[4x^2-49]/[8x^3+27]} *{ [4x^2+12x+9]/[2x^2-13x+21]}

4x^2-49 = (2x-7)(2x+7)

8x^3+27 = (2x+3)(4x^2-6x+9)

4x^2+12x+9 = (2x+3)(2x+3)

2x^2-13x+21 = (2x-7)(x-3)

Putting it all together, you can cancel the (2x-7)(2x+3) to get

(2x+7)(2x+3) / (x-3)(4x^2-6x+9)

Do (b) likewise. The key is to know how to factor these babies. Recognize differences of square and cubes.

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