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December 18, 2014

December 18, 2014

Posted by **John** on Tuesday, February 19, 2013 at 2:23am.

- Math -
**Reiny**, Tuesday, February 19, 2013 at 9:28amI will assume the "password" may start with a 0

So let's first of all choose the number of passwords

which would be C(2,1) x C(2,1) x C(2,1) x C(2,1) x C(2,1)

= 2^5 = 32

13578 would be in that choice, but not 31578

So we now have to "arrange" each of these 32 numbers

which would give us 32 x 5! = 3840

at a rate of 5 passwords per second it would take

3840/5 or 768 seconds to crack it

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