Posted by John on Tuesday, February 19, 2013 at 2:23am.
I will assume the "password" may start with a 0
So let's first of all choose the number of passwords
which would be C(2,1) x C(2,1) x C(2,1) x C(2,1) x C(2,1)
= 2^5 = 32
13578 would be in that choice, but not 31578
So we now have to "arrange" each of these 32 numbers
which would give us 32 x 5! = 3840
at a rate of 5 passwords per second it would take
3840/5 or 768 seconds to crack it
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