A sample of metallic element X, weighing 4.315g, combines with0.4810 L of Cl2 gas (at normal pressure and 20.0C) to form the metal chloride with the formula XCl. If the density of Cl2 gas under these conditions is 2.948g/L, what is the mass of chlorine? The amu of chlorine is 35.453. What is the atomic mass of X?

2X + Cl2 ==> 2XCl

mass X = 4.315g
L Cl2 = 0.4810; density = 2.948 g/L
mass Cl2 = 0.4810L x 2.948 g/L = 1.418g.

mols Cl = 1.418/35.453 = 0.0400 mols.
Since 0.0400 mols Cl reacted we know it must have done so with 0.0400 mols X.
mols = grams/atomic mass or
atomic mass = grams/mols
atomic mass X = 4.315/0.0400 = about 107 but you can finish.
Can you identify the metal X? Look at the atomic mass for Ag.

To find the mass of chlorine, we will first calculate the number of moles of chlorine gas using the given volume and density.

1. Calculate the mass of chlorine gas:
Mass of Cl2 = Density of Cl2 × Volume of Cl2
Mass of Cl2 = 2.948 g/L × 0.4810 L
Mass of Cl2 = 1.418 g

Now that we have the mass of chlorine gas, we can convert it to moles using the molar mass of chlorine:

2. Calculate the number of moles of Cl2:
Moles of Cl2 = Mass of Cl2 / Molar mass of Cl2
Moles of Cl2 = 1.418 g / 35.453 g/mol
Moles of Cl2 ≈ 0.04 mol

Since 1 mole of chlorine reacts with 1 mole of metal X to form XCl, we can say that the number of moles of metal X is also 0.04 mol.

Now, let's calculate the atomic mass of X:

3. Determine the mass of X:
Mass of X = Mass of XCl - Mass of Cl2
Mass of X = 4.315 g - 1.418 g
Mass of X = 2.897 g

Finally, we can find the atomic mass of X by dividing the mass of X by the number of moles:

4. Calculate the atomic mass of X:
Atomic mass of X = Mass of X / Moles of X
Atomic mass of X = 2.897 g / 0.04 mol
Atomic mass of X = 72.425 g/mol

Therefore, the atomic mass of element X is approximately 72.425 g/mol.