zoe, minh, and jake sold some tickets for a school fundraiser. each ticket cost $2. zoe sold 1/2 of the tickets. minh and jake sold the remaining tickets in the ratio 1:3. if zoe sold 36 more tickets than minh, how much money did the 3 students collect altogether?

To find the solution, we will follow these steps:

1. Find out how many tickets Zoe sold.
2. Calculate how many tickets Minh and Jake sold together.
3. Use the given ratio to determine the number of tickets sold by Minh and Jake individually.
4. Calculate the total number of tickets sold by all three students.
5. Multiply the total number of tickets by the cost per ticket to find the total amount of money collected.

Let's begin:

1. Zoe sold 1/2 of the tickets, so we can calculate the number of tickets she sold by dividing the total number of tickets by 2:
Zoe's tickets = (Total tickets) / 2

2. To find out how many tickets Minh and Jake sold together, we subtract the number of tickets Zoe sold from the total number of tickets:
Minh and Jake's tickets = Total tickets - Zoe's tickets

3. Given that Zoe sold 36 more tickets than Minh, we can set up the equation:
Zoe's tickets = Minh's tickets + 36

4. Since Minh and Jake sold tickets in the ratio 1:3, we can calculate the number of Minh's tickets by dividing the total tickets by the sum of the ratio parts (1 + 3):
Minh's tickets = (Minh and Jake's tickets) / (1 + 3)

Similarly, we can calculate the number of Jake's tickets by multiplying Minh's tickets by 3:
Jake's tickets = Minh's tickets × 3

5. The total number of tickets sold by all three students is the sum of Zoe's, Minh's, and Jake's tickets:
Total tickets sold = Zoe's tickets + Minh's tickets + Jake's tickets

6. Finally, to calculate the amount of money collected, we multiply the total number of tickets sold by the cost per ticket:
Total amount collected = Total tickets sold × (Cost per ticket)

By following these steps, we can find the answer to the question.

$84.00

i hate math

Let's solve this step-by-step.

1. Zoe sold 1/2 of the tickets, so let's represent the total number of tickets as "x". Zoe sold x/2 tickets.

2. Minh and Jake sold the remaining tickets. The ratio of Minh's tickets to Jake's tickets is 1:3. Let's represent Minh's tickets as "y" and Jake's tickets as "3y". So, the total number of tickets sold by Minh and Jake is y + 3y = 4y.

3. Zoe sold 36 more tickets than Minh. We can write this as: Zoe's tickets (x/2) = Minh's tickets (y) + 36.
Simplifying, we have: x = 2y + 72.

4. To find the value of y, we need to solve the system of equations:
x = 2y + 72 (Equation 1)
x = y + 3y (Equation 2)

From Equation 2, we have: x = 4y.
Substituting this value of x in Equation 1, we get: 4y = 2y + 72.
Solving this equation, we find: 2y = 72, y = 36.

5. Now that we have the value of y, we can find x (total number of tickets):
x = 4y = 4 * 36 = 144.

6. Each ticket cost $2, so the total amount collected by the students is (x+y+3y) * $2.
Substituting the values, we get: (144 + 36 + 3*36) * $2 = 360 * $2 = $720.

Therefore, the three students collected a total of $720.