if 45 g of calcium carbide reacts with 23 g of water, how many liters of acetylene can be produced, assuming the reaction goes to completion at 60 degrees fahrenheit and 763 mmHg

Question

if 45 g of calcium carbide reacts with 23 g of water, how many liters of acetylene can be produced, assuming the reaction goes to completion at 60 degrees fahrenheit and 763 mmHg

Answer 1

This is a limiting reagent problem. I know that because amounts are given for BOTH reactants.

CaC2 + 2HOH ==> C2H2 + Ca(OH)2
mols CaC2 = grams/molar mass.
mols H2O = grams/molar mass.

Convert mols CaC2 to mols C2H2 using the coefficients in the balanced equation.
Do the same for mols H2O.
It is likely that the answer will not be the same; therefore, one of them must be wrong. The correct answer in limiting reagent problems is ALWAYS the smaller value and the raagent producing that value is the limiting reagent. Then use PV = nRT to convert mols C2H2 to volume in L. F temperature must be converted to C then to kelvin. P must be converted to atm. The way the problem is worded I don't know if you are to correct for the vapor pressure of H2O or not. I suspect not.