Rearrange this expression into quadratic form, ax2 bx c = 0
0.20= ((x^2)/(55-x))
where a = 1, and identify the values of b and c.
c= -11
the correct form should say
ax^2 + bx + c = 0
for yours ....
.2(55-x) = x^2
x^2 = 11 - .2x
x^2 + .2x + 11 = 0
a=1
b=.2
c=11
To rearrange the given expression into quadratic form, we'll multiply both sides of the equation by (55-x):
0.20(55-x) = ((x^2)/(55-x))(55-x)
Multiplying each term:
11 - 0.20x = x^2
Now, let's move all terms to one side of the equation:
x^2 + 0.20x - 11 = 0
Comparing this with the quadratic form, ax^2 + bx + c = 0, we can identify the values of b and c:
b = 0.20
c = -11
To rearrange the given expression into quadratic form, ax^2 + bx + c = 0, we can follow these steps:
Step 1: Multiply both sides of the equation by (55-x) to eliminate the denominator:
0.20 * (55 - x) = x^2
Step 2: Distribute the 0.20 to both terms within the parentheses:
11 - 0.20x = x^2
Step 3: Move all terms to one side of the equation to achieve a "0" on the other side:
x^2 + 0.20x - 11 = 0
Now we have the expression in quadratic form, ax^2 + bx + c = 0, where:
a = 1 (coefficient of x^2)
b = 0.20 (coefficient of x)
c = -11 (constant term)