Posted by **jessica** on Monday, February 18, 2013 at 9:00pm.

what are the solution sets to x^5-2x^3+x=0 and how do you get them?

- trigonometry -
**jackie**, Monday, February 18, 2013 at 9:31pm
the answers are 1,-1, and 0 but i'm not sure how to explain how i got them.

- trigonometry -
**Reiny**, Monday, February 18, 2013 at 10:18pm
x^5 - 2x^3 + x = 0

x(x^4 - 2x^2 + 1) = 0

x(x^2 - 1)^2 = 0

so x = 0 or x^2 - 1 = 0 --->(x+1)(x-1) = 0

x = 0 or x =1 or x = -1

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