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November 28, 2014

November 28, 2014

Posted by **Lea** on Monday, February 18, 2013 at 5:24pm.

a1=(-3x1)2 +4=13

a2=(-3x2)2+4-40

a3=(-3x3)2+4=85

a4=(-3x4)2+4=148

a5=(-3x4)2+4=229

a6=(-3x4)2+4=328

The first six terms of the sequence are 13, 40, 85, 148, 229, 328

I keep coming up with these answers but there is suppose to be an error somewhere.

- Albebra 2 -
**Steve**, Monday, February 18, 2013 at 5:26pmAs you wrote it before,

-3x^2+4 = -3(x^2) + 4

You have tabulated (-3x)^2 + 4, which is very different

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