Monday

July 6, 2015

July 6, 2015

Posted by **Anonymous ** on Monday, February 18, 2013 at 4:49pm.

- College Algebra -
**Steve**, Monday, February 18, 2013 at 4:58pmavg rate of change is ∆y/∆x for the interval

∆y = f(10)-f(6) = 295-103 = 192

∆x = 10-6 = 4

avg rate of change is thus 192/4 = 48