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October 10, 2015
Posted by **Anonymous ** on Monday, February 18, 2013 at 4:49pm.

- College Algebra -
**Steve**, Monday, February 18, 2013 at 4:58pmavg rate of change is ∆y/∆x for the interval

∆y = f(10)-f(6) = 295-103 = 192

∆x = 10-6 = 4

avg rate of change is thus 192/4 = 48