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July 29, 2014

July 29, 2014

Posted by **Jacob** on Monday, February 18, 2013 at 4:41pm.

(x^(3)-8)/(x^(2)+9)

- Applied Calculus -
**JJ**, Monday, February 18, 2013 at 4:51pmThe rule is the denominator times the derivative of the numerator minus the numerator times the derivative of the denominator AND then put this answer over the denominator squared.

The deriv. of the numerator is 3x^2 and the deriv of the denom. is 2x

Can you finish from here?

- Applied Calculus -
**Steve**, Monday, February 18, 2013 at 4:51pmy = (x^3-8)/(x^2+9)

If y = u/v, y' = (vu' - uv')/v^2, so

y = ((3x^2)(x^2+9) - (x^3-8)(2x))/(x^2+9)^2

= (3x^4 + 27x^2 - 2x^4 + 16x)/(x^2+9)^2

= (x^4 + 27x^2 + 16x)/(x^2+9)^2

- Applied Calculus -
**Jacob**, Monday, February 18, 2013 at 4:57pmYeah, I was forgetful and forgot it was the Quotient Rule. Thank you all, I got it!

- Applied Calculus -
**Steve**, Monday, February 18, 2013 at 4:59pmjust curious -- if you forgot about the quotient rule, what did you try?

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