Calculate the mass of sliver chloride, AgCl, and dihydrogen monosulfide, H2S, formed when 85.6g of sliver sulfide, Ag2S, reacts with excess hydrochloric acid, HcL.
write the balanced equation:
Ag2S+ 2HCl >> 2AgCl + H2S
how many moles of silver sulfide does 85.6g make?
for each mole of silver sulfide, you get two moles of silver chloride. Convert that to mass
To calculate the mass of silver chloride (AgCl) and dihydrogen monosulfide (H2S) formed when 85.6g of silver sulfide (Ag2S) reacts with excess hydrochloric acid (HCl), we need to determine the balanced chemical equation for this reaction.
The balanced chemical equation for the reaction between silver sulfide and hydrochloric acid is:
Ag2S + 2HCl → 2AgCl + H2S
From the equation, we can see that 1 mole of silver sulfide reacts with 2 moles of hydrochloric acid to give 2 moles of silver chloride and 1 mole of dihydrogen monosulfide.
To calculate the number of moles of silver sulfide, we use the formula:
Number of moles = Mass / Molar mass
The molar mass of silver sulfide (Ag2S) is the sum of the molar masses of silver (Ag) and sulfur (S). From the periodic table, the molar masses of silver and sulfur are approximately 107.87 g/mol and 32.06 g/mol, respectively.
Molar mass of Ag2S = (2 × molar mass of Ag) + (1 × molar mass of S)
= (2 × 107.87 g/mol) + (1 × 32.06 g/mol)
= 243.8 g/mol
Now, we can calculate the number of moles of silver sulfide:
Number of moles of Ag2S = 85.6 g / 243.8 g/mol
≈ 0.351 moles
Since 1 mole of silver sulfide reacts with 2 moles of hydrochloric acid, we have twice the number of moles of silver chloride:
Number of moles of AgCl = 2 × 0.351 moles
≈ 0.702 moles
Similarly, 1 mole of silver sulfide gives 1 mole of dihydrogen monosulfide:
Number of moles of H2S = 0.351 moles
Finally, to calculate the mass of silver chloride and dihydrogen monosulfide, we use the formula:
Mass = Number of moles × Molar mass
The molar mass of silver chloride (AgCl) is approximately 143.32 g/mol, and the molar mass of dihydrogen monosulfide (H2S) is approximately 34.08 g/mol.
Mass of AgCl = 0.702 moles × 143.32 g/mol
≈ 100.54 g
Mass of H2S = 0.351 moles × 34.08 g/mol
≈ 11.94 g
Therefore, approximately 100.54 g of silver chloride (AgCl) and 11.94 g of dihydrogen monosulfide (H2S) will be formed in this reaction.