A piece of iron weighs 45 oz and has a volume of 10 in^3. Determine the density of iron in g/cm^3.
density=mass/iron
Now the wording "weighs 45oz" bothers me. This is one reason one should never use English units, it is not clear 45oz mass or force(weight). Nuts to using English units.
Lets assume it is mass.
density=45oz/10in^3*(1 in/2.54cm)^3*1lb/16oz*454grams/lb
= 4.5*454/(2.54^3*16)=7.791g/cm^3
check that
Thank you!!
To determine the density of iron, we need to convert the given measurements into units that are commonly used for density calculations.
First, we need to convert the weight of the iron from ounces to grams. We know that 1 ounce is approximately equal to 28.35 grams. So, to convert 45 ounces to grams, we multiply 45 by 28.35:
Weight in grams = 45 oz * 28.35 g/oz
Calculating this gives us:
Weight in grams ≈ 1275.75 g
Next, we need to convert the volume of the iron from cubic inches to cubic centimeters. We know that 1 cubic inch is equal to approximately 16.3871 cubic centimeters. So, to convert 10 cubic inches to cubic centimeters, we multiply 10 by 16.3871:
Volume in cubic centimeters = 10 in^3 * 16.3871 cm^3/in^3
Calculating this gives us:
Volume in cubic centimeters ≈ 163.871 cm^3
Finally, we can use the formula for density, which is calculated by dividing the weight by the volume:
Density = (Weight in grams) / (Volume in cubic centimeters)
Substituting the calculated values:
Density = 1275.75 g / 163.871 cm^3
Calculating this gives us:
Density ≈ 7.78 g/cm^3
Therefore, the density of the iron is approximately 7.78 g/cm^3.