Thursday
March 23, 2017

Post a New Question

Posted by on Monday, February 18, 2013 at 1:59pm.

The electric field between the plates of a paper-separated capacitor is 8.18×104 . The plates are 2.20 apart, and the charge on each plate is 0.795 .Determine the capacitance of this capacitor. Determine the area of each plate.

  • Physics - , Monday, February 18, 2013 at 4:54pm

    E= 8.18•10⁴ V/m
    d=2.2 mm
    q=0.775 μ C
    ε (paper)= 2.3
    (a) C=q/U
    E=U/d

    C=q/Ed = ...
    (b)
    ε₀=8.85•10⁻¹² F/m

    C= ε₀εA/d =>
    A=Cd/ε₀ε=...

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question