Posted by Nkosingiphile on Monday, February 18, 2013 at 9:26am.
A rectengular area is to be enclosed on three sides by fencing, an existing hedge forming the fourth side. Find the greatest area of the rectangle and its dimensions if 140mof fencing is available.

Math  Reiny, Monday, February 18, 2013 at 9:53am
let the length parallel to the hedge be y
let the width be x
so y + 2x = 140
y = 1402x
area = xy
= x(1402x) = 2x^2 + 140x
if you know Calculus:
4x + 140 = 0
x = 35
then y = 140  70 = 70
max area = 35(70) = 2450
If no Calculus:
complete the square to find the vertex
A = 2x^2 + 140x
= 2(x^2  70x)
= 2(x^2  70x + 1225  1225)
= 2( (x35)^2  1225)
= 2(x35)^2 + 2450
so the vertex is (35,2450)
giving us a max of 2450 when x = 35

Math  Jessica, Thursday, May 30, 2013 at 9:20pm
IDK but I'm not in eight grade, YET!! Comment, share, and love My pro in Facebook. Find me as Jessi Vertiz
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