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April 25, 2014

April 25, 2014

Posted by **Nkosingiphile** on Monday, February 18, 2013 at 9:26am.

- Math -
**Reiny**, Monday, February 18, 2013 at 9:53amlet the length parallel to the hedge be y

let the width be x

so y + 2x = 140

y = 140-2x

area = xy

= x(140-2x) = -2x^2 + 140x

if you know Calculus:

-4x + 140 = 0

x = 35

then y = 140 - 70 = 70

max area = 35(70) = 2450

If no Calculus:

complete the square to find the vertex

A = -2x^2 + 140x

= -2(x^2 - 70x)

= -2(x^2 - 70x + 1225 - 1225)

= -2( (x-35)^2 - 1225)

= -2(x-35)^2 + 2450

so the vertex is (35,2450)

giving us a max of 2450 when x = 35

- Math -
**Jessica**, Thursday, May 30, 2013 at 9:20pmIDK but I'm not in eight grade, YET!! Comment, share, and love My pro in Facebook. Find me as Jessi Vertiz

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