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March 29, 2017

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A bag contains 5 red, 4 blue and an unknown number of m green balls.
Two balls are drawn. If probability of both being green is 1/7 find m.

  • maths-urgently needed(probability) - ,

    I will assume the first ball drawn is NOT returned.

    prob(2green) = (n/(9+n) * ((n-1)/(8+n)) = 1/7

    7n^2 - 7n = n^2 + 17n + 72
    6n^2 - 24n - 72 = 0
    n^2 - 4n - 12 = 0
    (n-6)(n+2) = 0
    n = 6 or n = a negative, which is no good

    there were 6 green balls

    check:
    prob(2greens) = (6/15)(5/14) = 1/7

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