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January 25, 2015

Posted by **LaShawn** on Monday, February 18, 2013 at 2:35am.

16-n^2 n^2-7n-30

_________ __________

n^2-5n-36 * n^2-n-12

- Algebra -
**Reiny**, Monday, February 18, 2013 at 8:19amagain, I think you mean:

(16-n^2)/(n^2 - 5n - 36) * (n^2 - 7n - 30)/(n^2 - n - 12)

= (4-n)(4+n)/( (n-9)(n+4)) * (n-10)(n+3)/( (n-4)(n+3) )

= (n-10)/(n-9) , n ≠ ±4, -3

- Algebra -
**LaShawn**, Tuesday, February 19, 2013 at 8:45pmDivide

x^3y^2(x^2-3x-18)/xy^5(x^2-x-30)

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