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April 20, 2014

April 20, 2014

Posted by **Cassie** on Monday, February 18, 2013 at 1:08am.

I know how to work these problems out and I got 24,501.42m^2 but the computer is giving me an answer of 24,523.71...please check my answer...thank you

- Algebra -
**Reiny**, Monday, February 18, 2013 at 1:12amV = πr^2 h

= π (17^2)(27) = 24513.84

using 3.14 for π

V = 4.14(17^2)(27) = 24501.42

you are right!

- Algebra -
**Cassie**, Monday, February 18, 2013 at 1:13amYou meant to put 3.14 on the secon part...right?

- Algebra -
**Cassie**, Monday, February 18, 2013 at 1:25amsecond part I meant....right??

- Algebra -
**Jeff**, Monday, February 18, 2013 at 1:26amYou did the problem correctly. I am not sure how exactly you entered the numbers into the computer for pi, but it looks like with an answer of 24,523.71 the computer used an approzimation for pi based on the fraction 22/7.

22/7 = 3.142857....

If you plug the 22/7 instead of 3.14 you will get what the computer gets...

- Algebra -
**Cassie**, Monday, February 18, 2013 at 1:34amThank you Jeff....

- Algebra -
**Reiny**, Monday, February 18, 2013 at 2:01amI find it very odd, that the "computer" would use 22/7 for the value of π.

Surely it would have better value than that built in

Even the cheapest calculator will use about 9 decimal places for accuracy.

It looks to me that whatever "input routine" they are using, needs an immediate update to bring it into the 21st century.

- Algebra -
**Jeff**, Monday, February 18, 2013 at 3:09amReiny, Agreed, but that is what it appears to be using. I am guessing it was a software program and not the actual computer using that approximation.

What really irks me about pi is that most people know it is 3.1415....., but have NO idea what it actually represents....

- Algebra -
**Jeff**, Monday, February 18, 2013 at 3:12amBTW Cassie, please please always remember that pi is simply a circle's circumference divided by it's diameter. For every circle, no matter the size...

This is why it shows up in so many formulas for circles, cylinders, cones, etc.

- Algebra -
**Cassie**, Monday, February 18, 2013 at 8:46amok ....thank you

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