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Physics
Work and Power
Power Calculation
. Show that 480 W of power is expended by a weightlifter when lifting a 60-kg barbell a vertical distance of 1.2 m in a time interval of 1.5 s.
1 answer
power=work/time=mgh/timeinsseconds
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Similar Questions
Show that 480 W of power is expended by a weightlifter when lifting a 60-kg barbell a vertical distance of 1.2 m in a time
Top answer:
P = mg*d/t = 600 * 1.2/1.5 = 480 J/s = 480 Watts.
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Show that 480 W of power is expended by a weightlifter when lifting a 60-kg barbell a vertical distance of 1.2 m in a time
Top answer:
power=work/time=mgh/time=60*9.8*1.2/1.5
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Show that 480 W of power is expended by a weightlifter when lifting a 60-kg barbell a vertical distance of 1.2 m in a time
Top answer:
force = weight = m g = 60*9.8 = 588 Newtons distance = 1.2 m so potential energy gained = work done
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Show that 480 W of power is expended by a weightlifter when lifting a 60-kg barbell a vertical distance of 1.2 m in a time
Top answer:
Work done =mgh = 60 kg * 9.8 m/s² * 1.2 m = 705.6 j Power = work done / time = 705.6 j / 1.5 s. =
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Show that 480 W of power is expended by a weightlifter when lifting a 60-kg barbell a vertical distance of 1.2 m in a time
Top answer:
Power = F*d/t = mg*d/t =(60*10)*1.2/1.5 = 480 J/s = 480 Watts.
Read more.
Show that 480 W of power is expended by a weightlifter
when lifting a 60-kg barbell a vertical distance of 1.2 m in a time
Top answer:
Well, if a weightlifter manages to lift a 60-kg barbell 1.2 m in just 1.5 seconds, I must say
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Show that 480W of power is expended by a weightlifter when lifting a 60-kg barbell a vertical distance of 1.2m in a time
Top answer:
power=work/time=mgh/time
Read more.
hat power is expended by a weightlifter when lifting a 58- kg barbell a vertical distance of 0.70 m in a time interval of 1.9 s
Top answer:
To find the power expended by the weightlifter while lifting the barbell, we can use the formula:
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what power is expended by a weightlifter when lifting a 60kg barbell a vertical distance of 1.1m in a time interval of 2.0s
Top answer:
Fb = m*g = 60kg * 9.8N/kg = 588 N. = Force of the barbell. Power = F*d/t = 588*1.1/2=323.4 Joules/s
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What power is expended by a weightlifter when lifting a 56-kg barbell a vertical distance of 1.0 m in a time interval of 1.4 s .
Top answer:
56 kg * 9.8 m/s^2 * 1.0 m / 1.4 s = ? Watts
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