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April 1, 2015

April 1, 2015

Posted by **HELP** on Sunday, February 17, 2013 at 9:00pm.

Thank you for the answer of my 1st question..hope you could help me w/ this one.tnx

- DYNAMICS -
**bobpursley**, Sunday, February 17, 2013 at 9:30pmv=12-3t^2

acceleration= -6t at t=4, acceleration is -24m/s^2

displacement=INTEGRAL velocity dt

= INT(12-3t^2)dt= 12t-t^3 from t=0 to 10

= 120-1000=-860

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