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March 30, 2015

March 30, 2015

Posted by **Amy** on Sunday, February 17, 2013 at 6:20pm.

4.74 s

2.65 s

3.35 s

5.96 s

- Physics -
**drwls**, Sunday, February 17, 2013 at 8:15pmAssume that the elevator accelerates at a constant rate a while going up X = 50 m in time t. (Assume it doesn't slow down until it gets to higher floors). The acceleration, a, will be given by

(1/2)at^2 = X

a = 2X/t^2

Cable tension at the breaking point is

95,500 = M(g + a) = 65,660 + M*a

M*a = 29840 N

a = (29840)/6700 = 4.45 m/s^2

Minimum time t = sqrt(2X/a) = 4.74 s

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