MATH Algebra 2
posted by Blair on .
x^26>5x
6x^25x+1<0
Solve (using any method), write your answer in interval notation and graph the solution set.

1. x^2 + 5x  6 > 0
(x+6)(x1) > 0
critical values are x = 6 and x = 1
so the parabola y = x^2 + 5x  6 crosses the xaxis at 6 and 1, and knowing about the basic shape, (it opens upwards), we can state that it will be above for
x < 6 OR x > 1
2. 6x^2  5x + 1 < 0
(6x  1)(x + 1) < 0
critical values are .....
since we want to be below the xaxis ( < 0)
.......
take it from here, and use the notation that was taught to you, 
[1/3, 1/2]