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Posted by on Sunday, February 17, 2013 at 4:35pm.

A block of mass 3 kg is at rest on an incline. The coefficient of state friction between the block and incline is 0.34. What is the maximum angle of the incline such that the block will not slide down the plane?

  • Physics - , Monday, February 18, 2013 at 5:17pm

    Wb = m * g = 3kg * 9.8N/kg = 29.4 N. = Wt. of the block.

    Fb = 29.4N. @ Ao. = Force of the block.
    Fp = 29.4*sinA = Force parallel to the incline.
    Fv = 29.4*cosA = Force perpendicular to the incline.

    Fs = u*Fv = 0.34 * 29.4*cosA = 10*cosA.

    Fp-Fs = m*a.
    29.4*sinA-10*cosA = m*0 = 0
    29.4*sinA = 10*cosA
    Divide both sides by cosA:
    29.4*(sinA/cosA) = 10
    Replace sinA/cosA with tanA:
    29.4*tanA = 10
    tanA = 0.34
    A = 18.8o

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