Posted by **unknown** on Sunday, February 17, 2013 at 1:29pm.

A two-qubit system was originally in the state 34|00⟩−5√4|01⟩+14|10⟩−14|11⟩, and then we measured the first qubit to be 0. Now, if we measure the second qubit in the standard basis, what is the probability that the outcome is 0?

unansweredA two-qubit system was originally in the state 34|00⟩−5√4|01⟩+14|10⟩−14|11⟩, and then we measured the first qubit to be 0. Now, if we measure the second qubit in the standard basis, what is the probability that the outcome is 0?

- Physics -
**qwerty**, Sunday, February 17, 2013 at 3:09pm
9/14

## Answer this Question

## Related Questions

- Physics - A two-qubit system was originally in the state 34|00⟩−5&#...
- quantum mechanics - Suppose we have a qubit in the state |ψ⟩=12|0&#...
- quantummechanics - The following circuit is designed for testing whether |u&#...
- Physics - Alice and Bob share a state a|++⟩+b|−−⟩, ...
- Physics - We have a qubit in the state |ϕ⟩=3√2|0⟩+12|1...
- Physics - Suppose we have a one-qubit unitary U that maps |0⟩ to 12|0&#...
- Physics - Suppose we have a one-qubit unitary U that maps |0⟩ to 13|0&#...
- Quantum Physics - Suppose we have two qubits in the state α|00⟩+&#...
- Physics - If the first qubit is in the state 13√|0⟩+2√3√...
- Physics - Suppose we have a qubit in the state |ψ⟩. We know that if ...

More Related Questions