Physics
posted by Anonymous on .
A spring, (spring constant of 400 N/m) is displaced .75 m from its equilibrium position. An 8kg mass is connected to the spring and it is allowed to oscillate horizontally with Simple Harmonic Motion. What is the Kinetic Energy of the mass?

A=0.75 m, m=8 kg, k= 400 N/m
ω=sqrt(k/m) = …
x=Acosωt
v=  Aωsinωt
v(max) = Aω
KE=mv²/2 =0.5m A²ω²sinωt
KE(max) = 0.5m A²ω²