Three circles are placed on a plane in such a way that each circle just touches the other two , each having a radius of 10 cm.find the area of region enclosed by them

Find the area of three sectors of 60 degrees by the formula (pi * r * r)*(60 / 360) [bcoz the angle of each sector is 60 degreeand r would be 10 cm]

multiply the value u have got with 3 ... bcoz there are 3 sectors .... the result would be 1100/7 cm^2
Now find the area of equilateral triangle of side 20 cm [bcoz each radius is 10 cm and two radius makes up one side of the triangle].....
the formula is {(root 3)/4} * a^2 .......the result would be 173.2 cm^2 ....
subtract 1100/7 from 173.2 .... u would get the answer ....
it 's 173.2 - 157.14 = 16.06 cm2 .......
I have taken value of pi as 22/7 and that of root 3 as 1.732