Friday

April 18, 2014

April 18, 2014

Posted by **Isis** on Saturday, February 16, 2013 at 11:14pm.

b) A ball (0.5 kg) is thrown with a velocity of 15 m/s. A receiver catches the ball and brings it to rest is 0.02 s.

a) What is the change in momentum?

c) A ball (0.5 kg) is thrown with a velocity of 15 m/s. A receiver catches the ball and brings it to rest is 0.02 s.

a) What is the change in momentum of the ball?

b) What is the impulse delivered to the ball?

c) What force is exerted on the ball?

d) A ball (0.40 kg) is moving with a velocity of 18 m/s. A player strikes the ball and causes it to move in the opposite direction with a velocity of 22 m/s. The player exerts a force of 5500 N.

a) What is the change in momentum of the ball?

b) What is the impulse delivered to the ball?

c)How long is the foot in contact with a ball?

~formula's~

J= Ft

J= P

Ft=mvf-mvi

PLease help me!! :)

- Physics ~IMPULSE~ -
**Damon**, Sunday, February 17, 2013 at 8:08amThese are all the same so I am only going to do d

initial momentum = .4 * 18 = + 7.2 kg m/s

final momentum = - .4 * 22 = - 8.8 kg m/s

change in momentum = -8.8 - 7.2 = -16 kg m/s

impulse = change in momentum = -16 kg m/s

Force = change in momentum / change in time

so

-5500 = -16 /t

t = .003 seconds

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