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Posted by on Saturday, February 16, 2013 at 3:43pm.

Find a formula for the exponential function that satisfies h(2)=22 and h(4)=14.08

  • Math - , Saturday, February 16, 2013 at 3:58pm

    if h(x) = ae^bx,
    just plug in your values:
    22 = ae^2b
    14.08 = ae^4b

    divide one by the other, and the a's cancel

    14.08/22 = .64 = e^2b
    e^b = .8

    22 = a*.64
    a = 34.375

    h(x) = 34.375 e^bx = 34.375 * 0.8^x

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