Posted by **Stacy** on Saturday, February 16, 2013 at 3:43pm.

Find a formula for the exponential function that satisfies h(2)=22 and h(4)=14.08

- Math -
**Steve**, Saturday, February 16, 2013 at 3:58pm
if h(x) = ae^bx,

just plug in your values:

22 = ae^2b

14.08 = ae^4b

divide one by the other, and the a's cancel

14.08/22 = .64 = e^2b

e^b = .8

22 = a*.64

a = 34.375

h(x) = 34.375 e^bx = 34.375 * 0.8^x

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