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Posted by on Saturday, February 16, 2013 at 11:44am.

Find to find equation of the tangent line y=x^4-x^3-x^2-x+1 at the point x=1

  • Math - , Saturday, February 16, 2013 at 2:07pm

    Is the calculus?

    If so, take the derivative of y which would be 4x^3 - 3x^2-2x -1
    Let x =1 to find the slope
    4-3-2-1 = m = -2

    find the value of y when x = 1

    You will then have the slope and a point to use to find the equation using y=mx+b

  • Math - , Saturday, February 16, 2013 at 2:51pm

    so i found the y=-1
    then i subbed into y=mx+b and got -1=-2(1)+b
    1=b

    then my equation would be -1=-2(1)+1

    is that right?

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