Post a New Question


posted by .

Find to find equation of the tangent line y=x^4-x^3-x^2-x+1 at the point x=1

  • Math -

    Is the calculus?

    If so, take the derivative of y which would be 4x^3 - 3x^2-2x -1
    Let x =1 to find the slope
    4-3-2-1 = m = -2

    find the value of y when x = 1

    You will then have the slope and a point to use to find the equation using y=mx+b

  • Math -

    so i found the y=-1
    then i subbed into y=mx+b and got -1=-2(1)+b

    then my equation would be -1=-2(1)+1

    is that right?

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question