Posted by **Paul** on Saturday, February 16, 2013 at 11:44am.

Find to find equation of the tangent line y=x^4-x^3-x^2-x+1 at the point x=1

- Math -
**JJ**, Saturday, February 16, 2013 at 2:07pm
Is the calculus?

If so, take the derivative of y which would be 4x^3 - 3x^2-2x -1

Let x =1 to find the slope

4-3-2-1 = m = -2

find the value of y when x = 1

You will then have the slope and a point to use to find the equation using y=mx+b

- Math -
**Paul**, Saturday, February 16, 2013 at 2:51pm
so i found the y=-1

then i subbed into y=mx+b and got -1=-2(1)+b

1=b

then my equation would be -1=-2(1)+1

is that right?

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