maths
posted by reshma on .
if A=(3,5) and B=(4,1).find the equation of locus of point p which are equidistant from points A and B

such a point must lie on the rightbisector of AB
midpoint of AB =(7/2 , 3)
slope of AB = (15)/(43) = 4
so slope of perpendicular = 1/4
equation:
y3 = (1/4)(x7/2)
y  3 = (1/4)x  7/8
y = (1/4)x +3  7/8
y = (1/4)x + 17/8