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March 31, 2015

March 31, 2015

Posted by **reshma** on Saturday, February 16, 2013 at 9:07am.

- maths -
**Reiny**, Saturday, February 16, 2013 at 10:16amsuch a point must lie on the right-bisector of AB

midpoint of AB =(7/2 , 3)

slope of AB = (1-5)/(4-3) = -4

so slope of perpendicular = 1/4

equation:

y-3 = (1/4)(x-7/2)

y - 3 = (1/4)x - 7/8

y = (1/4)x +3 - 7/8

y = (1/4)x + 17/8

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