Write an equation representing the oxidation of each of the following.
I'm on 3-hexanol.
And this is what I got
-> [o] 3-hexanal and further oxidation I know you get 3-hexananoic acid. I don't know how to make this in the line formula. Can I put the -OH and the double bond O on carbon 3. Or is there no further reaction with this molecule.
The way that you have set up the nomenclature, you are implying that you will get a carboxylic acid from 3-hexanol; this is not true. You will get a ketone, not an acid.
To represent the oxidation of 3-hexanol, you can start with the formula of 3-hexanol and show the oxidation product where appropriate.
The formula for 3-hexanol is C6H14O.
1. Oxidation to 3-hexanal: In this step, the -OH group on carbon 3 is oxidized to a carbonyl group (C=O). Symbolically, this is represented as [O]. So, the equation for the oxidation of 3-hexanol to 3-hexanal would be:
C6H14O -> [O] C6H12O (3-hexanal)
2. Further oxidation to 3-hexanoic acid: If you continue the oxidation of 3-hexanal, the aldehyde group (C=O) is oxidized to a carboxylic acid group (COOH). Symbolically, this is also represented as [O]. So, the equation for the further oxidation of 3-hexanal to 3-hexanoic acid would be:
C6H12O -> [O] C6H10O2 (3-hexanoic acid)
In the line formula, you can represent 3-hexanoic acid as follows:
H
|
H - C - C - C - C - C - COOH
|
H
Please note that it is essential to place the carbonyl groups (C=O) in the correct positions within the carbon chain.