Posted by **Dee** on Friday, February 15, 2013 at 9:30am.

A model rocket launches with an initial velocity of 6 m/s, at an angle of 90 degrees (with respect to the horizon). The rocket's engine provides an acceleration of 2.2 m/s2, acting in the same direction as the initial velocity. After 20 seconds, the rocket engine cuts out.

What is the maximum height attained by the rocket?

- Physics -
**bobpursley**, Friday, February 15, 2013 at 10:20am
at twenty seconds,

vf=vi+at=50.4 m/s check that.

h=(vi*20+1/2 a t^2)= 120+1.1*400=560 check that.

now, how much higher did it go, with an initial velocity of 50.4m/s

vf at top=0

vf^2=vi^2+2ad

0=50,4^2-19.8d solve for d

Now add d to 560m

## Answer This Question

## Related Questions

- PHYSICS - A catapult launches a rocket at an angle of 56.9° above the horizontal...
- physics - A catapult launches a rocket at an angle of 47.5° above the horizontal...
- physics - A test rocket is launched vertically from ground level (y = 0 m), at ...
- Physics - A rocket of mass 1.0x10^3kg is being fired to a height of 5.0 x 10^3 m...
- physics - i need help figuring out what formaula to use for finding the final ...
- phyicis - Homer Hickham and his buddies launched model rockets in the late 1950'...
- Physics - A test rocket is launched vertically from ground level (y=0m), at time...
- physics - A test rocket is launched vertically from ground level (y = 0 m), at ...
- physics - Model rocket engines are sized by thrust, thrust duration, and total ...
- physics - A catapult launches a test rocket vertically upward from a well, ...

More Related Questions