Posted by **Anonymous** on Friday, February 15, 2013 at 6:41am.

In the finals of a rugby tournament, two teams play a best of 5 series. Each team has a probability of 1/2 of winning the first game. For each subsequent game, the team that won the previous game has a 7/10 chance of winning, while the other team has a 3/10 chance of winning. If p is the probability that the series lasts exactly 4 games, what is ⌊1000p⌋?

- maths -
**Reiny**, Friday, February 15, 2013 at 10:27am
I am not familiar with your notation of ⌊1000p⌋

but I would do it this way:

after a W prob(W) = 7/10 , prob(L) = 3/10

after a L, Prob(W) = 3/10, prob(L) = 7/10

To have a 4-game series in a best of 5 setup, the winning team could win in these ways

LWWW --- (1/2)(3/10)(7/10)(7/10) = 147/2000

WLWW --- (1/2)(3/10)(3/10)(7/10) = 63/2000

WWLW --- (1/2)(7/10)(3/10)(3/10) = 63/2000

Prob = (147+63+63)/2000 = 273/2000

## Answer this Question

## Related Questions

- math - Two teams play an extended series of 100 volleyball games. Team A wins ...
- math - Two teams play an extended series of 100 volleyball games. Team A wins ...
- plllllllllls help maaaaaaaaaath - Two teams play an extended series of 100 ...
- Probability - Two equally matched teams are playing a game of volleyball. Each ...
- Data managment math - 5: In the best-of -five hockey series , the probability of...
- math - A basketball tournament starts with 64 teams. After one loss the team is ...
- 5th Grade ADV. Math - Four teams are playing in a tournament. Each team will ...
- Math - 1. A tennis player wins a math 55% of the time when she serves first and ...
- Data managment math - 1: What is the probability that at least two of the 12 ...
- Math - How do you solve: n is 2 given that it is even The directions say "let n ...

More Related Questions