Post a New Question

MATHS GEOMETRY!!! URGENT PLEASE.

posted by on .

A triangle has side lengths 10,17 and 21cm. Find the length of the shortest altitude.

And please show working out to help me understand.

  • MATHS GEOMETRY!!! URGENT PLEASE. - ,

    if a,b,c = 10,17,21,

    a^2 = b^2+c^2-2bc cos C, so
    cosC = (17^2 + 21^2 - 10^2)/(2*17*21) = 15/17
    so, sinC = 0.47

    figure sinA and sinB the same way

    If the altitudes from A,B,C are Ha,Hb,Hc, then

    Hc = a*sinB = b*sinA

    Figure the other altitudes in like wise.

    OR--------
    figure the area using Heron's formula.
    Then since 1/2 c*Hc = area
    Hc = 2*area/c

    Since the area does not change, the shortest altitude is on the longest side.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question