Mechanics _ physics
posted by Precious on .
A wheel rotating with an angular velocity of 16rad/sec is slowed to an angular velocity of 4rad/sec by an angular acceleration of 2rad/sec^2.find
a. The angle turned in the process of slowing down
b. The time required
a. V^2 = Vo^2 + 2a*d.
d = (V^2-Vo^2)/2a.
d = (16-256)/-4 = 60 Rad.
b. t = (V-Vo)/a = (4-16)/-2 = 6 s.